x^2-8x+28=0

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Solution for x^2-8x+28=0 equation:


Simplifying
x2 + -8x + 28 = 0

Reorder the terms:
28 + -8x + x2 = 0

Solving
28 + -8x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-28' to each side of the equation.
28 + -8x + -28 + x2 = 0 + -28

Reorder the terms:
28 + -28 + -8x + x2 = 0 + -28

Combine like terms: 28 + -28 = 0
0 + -8x + x2 = 0 + -28
-8x + x2 = 0 + -28

Combine like terms: 0 + -28 = -28
-8x + x2 = -28

The x term is -8x.  Take half its coefficient (-4).
Square it (16) and add it to both sides.

Add '16' to each side of the equation.
-8x + 16 + x2 = -28 + 16

Reorder the terms:
16 + -8x + x2 = -28 + 16

Combine like terms: -28 + 16 = -12
16 + -8x + x2 = -12

Factor a perfect square on the left side:
(x + -4)(x + -4) = -12

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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